Classical Genetics.
Vocabulary
:History
:
Using a Punnett square:

Punnett square

Step 1

Step 2

Dihybrid crosses

f1 generation

f2 generation
Probability & Genetics
The probability for each toss individually resulting in heads is 1/2.
Thus: to obtain the probability of two successively one multiplies their individual probabilities. (1/2) X (1/2) = 1/4
If both parents are Bb what is the probability of the offspring being bb?
The offspring must receive a b gamete from both parents.
The probability of a b sperm is 1/2
The probability of a b ovum is also 1/2
Thus the probability of a bb offspring is the product of the two individual probabilities :(1/2)X(1/2)=1/4
There are 2 mutually exclusive ways this can occur:
The probability for each event (H/T) is 1/2
Thus the probability of situation 1 can be derived using the product law:
(1/2) X (1/2) = 1/4
The probability of situation 2 can thus be the same:
(1/2) X (1/2) = 1/4
Since the individual events are mutually exclusive, the total probability of either occurring can be derived using the sum law:
(1/4) + (1/4) = 1/2
Chromosomes and Classical Genetics
Sex Linkage:

Example:
Crossing Over / Recombination
As seen before, genetic recombination can occur during synapsis of meiosis. This can explain much of the variability which challenged the principles of independent assortment through chromosome migration.

Gene Mapping

Example Gene Map
Other Factors Effecting Phenotypic Expression:
Multiple alleles:
ABO Blood typing
Gene interaction:
Continuous variation:

Continuous Variation of Human Height
Environmental effects:
Incomplete Dominance.

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Mr. Stanley
Last updated: March 11, 2004